Respuesta :
Answer:
- Red flowers: 27/256
- Pink flowers: 117/256
- White flowers: 112/256
Explanation:
Available data:
- Gene A controls the conversion of a white pigment, P0, into another white pigment, P1. The dominant allele "A" allows this reaction to occur, while the recessive allele "a" does not.
- Gene B controls the conversion of the white pigment, P1, into a pink pigment, P2; the dominant allele, "B", allows this reaction to occur, while the recessive allele "b" does not
- The dominant allele, "C", of the third gene specifies an enzyme that converts the pink pigment, P2, into a red pigment, P3; its recessive allele, "c", produces an altered enzyme that cannot carry out this conversion.
- The dominant allele, "D", blocks the reaction P2 → P3. Its recessive allele, d, does not block this reaction.
This is:
In the presence of the dominant alleles A, B, and C, the three reactions might occur:
Po (white 0) ----> P1 (White 1) ----> P2 (Pink) ----> P3 (Red)
A B C
In the presence of the recessive alleles a, b or c, the three reactions or some of them might not occur ( the X represents the inhibition of the reaction):
Po (white 0) --X--> P1 (White 1) --X--> P2 (Pink) --X--> P3 (Red)
a b c
In the presence of allele D, the last reaction is not possible, because D inhibits the action of C
P2 (Pink) --X--> P3 (Red)
C + D
So, in order to get Red flowers we must have the next genotype:
A-B-C-dd (The three reactions can occur, and D must be absent)
To get Pink flowers we must have the next genotypes:
A-B-C-D- (D Inhibits C, hence it inhibits the third reaction) or A-B-ccD- or A-B-ccdd (cc does not allow the third reaction to happen, independently of the D gene presence)
To get White flowers we must have the next genotypes:
aaB-C-D-, aabbC-D-, aaB-ccD-, aabbccD-, aabbccdd, aaB-C-dd, aaB-ccdd, aabbC-dd, A-bbC-D-, A-bbccD-, A-bbC-dd, A-bbccdd
(aa must be present to get a white0 flower, or bb must be present to get a white1 flower)
In the proposed problem, we have that the parentals are AAbbCCDD and aaBBccdd, so we can tell that the whole F1 progeny will be heterozygous for the four genes, this is AaBbCcDd.
Knowing that these four genes assort independently, then we can infer that the F2 will have the next genotypic proportions for each gene:
AA + Aa=3/4
aa= 1/4
BB + bb= 3/4
bb = 1/4
CC + Cc = 3/4
cc= 1/4
DD + Dd =3/4
dd= 1/4
So, to get the proportions of each trait, we must multiply the respective genotypic proportions, like this:
- Red: A- x B- x C- x dd: 3/4 x 3/4 x 3/4 x 1/4 = 27/256
- Pink: A- x B- x C- x D-: 3/4 x 3/4 x 3/4 x 3/4 = 81/256
A- x B- x cc x D-: 3/4 x 3/ x 1/4 x 3/4 = 27/256
A- x B- x cc x dd: 3/4 x 3/4 x 1/4 x 1/4= 9/256
By summing these proportions, we can get the proportion of all the pink flowers: 27/256 + 81/256 + 27/256 + 9/256= 117/256
- White: To get the proportion of white flowers, you can repeat the same multiplications as before for each possible white genotype and then sum the results, as we did for pink flowers. Or you can extract from the total number of flowers (256), the amounts of red and pink flowers (27 and 117). This is: 256 - (27 + 117) = 112.
Then 112/256 is the proportion of white flowers.