Answer:
[tex]627031 kgm^2/s[/tex]
Explanation:
First convert angular speed from 6.2 rev/s to rad/s knowing that each revolution is 2π rad:
[tex]\omega = 6.2 * 2\pi = 38.96 rad/s[/tex]
The we can calculate the moments of inertia of the satellite by summing up the 2 moments of inertia of the solid sphere and the 2 rods at their ends:
[tex] I = I_s + 2I_r[/tex]
[tex]I = \frac{2}{5}MR^2 + 2\frac{1}{3}mL^2[/tex]
[tex]I = \frac{2}{5}10000*2^2 + 2\frac{1}{3}16*3^2[/tex]
[tex]I = 16000 + 96 = 16096 kgm^2[/tex]
Then the angular momentum is the product of angular velocity and moment of inertia
[tex]\omega I = 38.96 * 16096 = 627031 kgm^2/s[/tex]
