Answer:
Arrangement A will have a greater heat transfer
Explanation:
the rate of heat conduction between two materials of different temperatures is given as
[tex]\frac{\Delta Q}{\Delta t}=\frac{-KA \Delta T}{ L}[/tex]
This formula shows the following:
Arrangement A has a shorter transfer medium and a larger equivalent cross sectional area, because the two rods are arranged in a parallel configuration.
whereas, Arrangement a has a longer transfer medium and a smaller cross sectional area, since the two rods are arranged end to end