Answer:
About 13 cm
Explanation:
We are given that
Length of cylinder,l=15 cm=[tex]15\times 10^{-2} m[/tex]
1 m=100 cm
h=4 cm=[tex]\frac{4}{100}=0.04 m[/tex]
Horizontal velocity of the existing water stream=[tex]v=\sqrt{2gh}[/tex]
Where [tex]g=9.8m/s^2[/tex]
Using the formula
[tex]v=\sqrt{2\times 9.8\times 0.04}=0.885m/s[/tex]
h'=l-h=15-4=11 cm=[tex]\frac{11}{100}=0.11 m[/tex]
Initial velocity of water stream,u=0
[tex]t=\sqrt{\frac{2h'}{g}}=\sqrt{\frac{2\times 0.11}{9.8}}=0.15 s[/tex]
Distance, d=vt
Using the formula
[tex]d=0.885\times 0.15=0.133 m[/tex]
[tex]d=0.133\times 100=13.3 cm\approx 13 cm[/tex]
