Question:
The question is incomplete. The width and radius was not given. For this answer, take the radius of slot as 8mm and the width as 45mm
Answer:
Total elongation = 4.426 * 10⁻³mm
Explanation:
Given Data:
L = 510 mm
E = 68 Gpa = 68 * 10^3N/mm²
b = 45 mm
t = 8 mm
P = 170 MPa
Calculating the cross sectional area for section A, we have
A₁= b*t
= 45 * 8
= 360mm²
Calculating the deformation of section A, we have
б₁ = (P (L/4))/(A₁E)
Substituting, we have
б₁ = (170*(510/4))/(360*68*10³)
= 21675/24480000
= 8.85*10⁻⁴mm
The cross sectional area of section 2 is given as
A₂ = 2/3 * b* t
Substituting, we have
A = 2/3 * 45 * 8
=240mm
The deformation of section 2 is given by the formula,
б₂ = P (L/2)/A₂E
Substituting, we have
б₂ = (170*(510/2))/(240*68*10³)
= 43350/16320000
= 2.656 * 10⁻³mm
Note, the cross sectional area of section 3 is the same with that of section 1, therefore, deformation for section 1 and section 3 are the same.
б₃ = 8.85*10⁻⁴mm
Total elongation = б₁ +б₂ + б₃
=8.85*10⁻⁴mm +2.656 * 10⁻³mm + 8.85*10⁻⁴mm
= 4.426 * 10⁻³mm
