Given:
Given that the square pyramid.
The slant height of the square pyramid is 3 inches.
The base of the pyramid is 4 inches.
We need to determine the net surface area of the square pyramid.
Area of the base:
The area of the base can be determined using the formula,
[tex]A=a^2[/tex]
where a is the base of the pyramid.
Substituting a = 4, we get;
[tex]A=4^2[/tex]
[tex]A=16 \ in^2[/tex]
Thus, the area of the base is 16 square inches.
Perimeter of the base:
The perimeter of the base is given by
[tex]p=4+4+4+4[/tex]
[tex]p=16 \ in[/tex]
Thus, the perimeter of the base is 16 inches.
Surface area of the pyramid:
The surface area of the pyramid can be determined using the formula,
[tex]SA=A+\frac{1}{2} p s[/tex]
where A is the area of the base,
p is the perimeter of the base and
s is the slant height.
Substituting the values, we have;
[tex]SA=16+\frac{1}{2}(16)(3)[/tex]
[tex]SA=16+\frac{48}{2}[/tex]
[tex]SA=16+24[/tex]
[tex]SA=40 \ in^2[/tex]
Thus, the surface area of the square pyramid is 40 square inches.
