Sunlight, with an intensity of 637 W / m 2 , strikes a flat collecting surface perpendicularly and is totally absorbed. The area of the surface is 8.33 m 2 . What is the force F in micronewtons that acts on the surface due to the sunlight?

Respuesta :

Answer:

Force of 17.6 micrometer is acting on the surface due to the sunlight.

Explanation:

Given that,

Intensity of sunlight is [tex]I=637\ W/m^2[/tex]

It strikes a flat collecting surface perpendicularly and is totally absorbed. The area of the surface is [tex]A=8.33\ m^2[/tex]

[tex]P=F\times v[/tex]

So, force is given by :

[tex]F=\dfrac{IA}{c}[/tex]  

c is speed of light

[tex]F=\dfrac{637\times 8.33}{3\times 10^8}\\\\F=17.6\ \mu N[/tex]

So, force of 17.6 micrometer is acting on the surface due to the sunlight.