Answer:
[tex]0.56[/tex]
Step-by-step explanation:
GIVEN: There is a [tex]60\%[/tex] chance of rain on Saturday and a [tex]20\%[/tex] chance of rain on Sunday. Assume that the event that it rains on Saturday is independent of the event that it rains on Sunday.
TO FIND: What is the probability that it rains on exactly one day over the weekend.
SOLUTION:
Probability of rain on Saturday [tex]P(A)=0.6[/tex]
Probability of not raining on Saturday [tex]P(A^{'}) =1-0.6=0.4[/tex]
Probability of rain on Sunday [tex]P(B)=0.2[/tex]
Probability of not raining on Saturday [tex]P(B^{'})=1-0.2=0.8[/tex]
Probability of raining exactly one day over the weekend
[tex]=\text{Probability it rains only on Saturday}+\text{Probability it rains only on Sunday}[/tex]
[tex]=P(A)\times P(B^{'})+P(B)\times P(A^{'})[/tex]
[tex]=0.6\times0.8+0.2\times0.4[/tex]
[tex]=0.56[/tex]
Hence probability of raining exactly only one day over the weekend is [tex]0.56[/tex]