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A student prepares a solution of sodium chloride by dissolving 116.9 g of NaCl into enough water to make 1.00 L of solution. How would the student properly label this solution? A. 2.00 M NaCl B. 116.9 g/ L NaCl C. 116.9 M NaCl D. 2.00 M/L NaCl

Respuesta :

Answer: The molarity of the solution is 2.00 M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in L = 1.00 L

moles of solute =[tex]\frac{\text {given mass}}{\text {molar mass}}=\frac{116.9g}{58.5g/mol}=2.00moles[/tex]

[tex]Molarity=\frac{2.00mol}{1.00L}=2.00M[/tex]

Thus the molarity of the solution is 2.00 M

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