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The horizontal surface on which the 2.0 - kg block slides is frictionless. The speed of the block before it touches the spring is 9.0 m/s. How fast is the block moving at the instant the spring has been compressed 174.5 mm

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Answer:

0.918 seconds

Explanation:

M = 2kg

V = 9.0 m/s

g = 9.8 m/s

F = Mg cosΘ

Θ = 0°

But F = Ma

a = v / t

F = m*v / t

Mv / t = mg cos0

V / t = g

t = v / g

t = 9.0 / 9.8

t = 0.918s

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