Question:
Assumptions
Voltage of battery = 24 V
Resistance on the right,20Ω parallel to 10 Ω resistor
Answer:
For the current out of the battery to be the same as when the switch was opened with the switch closed, the resistance on the resistor on the right must be approximately 20/3 Ω
Explanation:
We note that the switch in the assumption is on the same line as the 20 Ω resistor.
With a voltage of 24 V, and the switch closed, we have;
Total resistance = [tex]\frac{1}{\frac{1}{10} +\frac{1}{20} } = \frac{20}{3} \Omega[/tex]
Current out of voltage, I = Voltage/(total resistance)
= 24 ÷ 20/3 = 24 × 3/20 = 18/5 A
Therefore, with the switch opened, we get
Resistance on the right = Initial total resistance [tex]= \frac{20}{3} \Omega[/tex]
Therefore, with the switch opened, the resistance on the resistor on the right must be approximately equal to the resultant resistance of the two resistances in parallel.
