Assume that blood pressure readings are normally distributed with a mean of 124 and a standard deviation of 6.4. If 64 people are randomly​ selected, find the probability that their mean blood pressure will be less than 126. Round to four decimal places.

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Answer:

99.38%

Step-by-step explanation:

We have that the mean (m) is equal to 124, the standard deviation (sd) 6.4 and the sample size (n) = 64

They ask us for P (x <126)

For this, the first thing is to calculate z, which is given by the following equation:

z = (x - m) / (sd / (n ^ 1/2))

We have all these values, replacing we have:

z = (126 - 124) / (6.4 / (64 ^ 1/2))

z = 2.5

With the normal distribution table (attached), we have that at that value, the probability is:

P (z <2.5) = 0.9938

The probability is 99.38%

Ver imagen jmonterrozar

According to the normal distribution table, the probability that their mean blood pressure will be less than 126 is 99.38%.

Given :

Blood pressure readings are normally distributed with a mean of 124 and a standard deviation of 6.4.

The formula of z-score is used to determine the probability that their mean blood pressure will be less than 126. The formula of z score is given by:

[tex]\rm z = \dfrac{x-m}{\dfrac{\sigma }{\sqrt{n} }}[/tex]

Now, substitute the values of known terms in the above equation.

[tex]\rm z = \dfrac{126-124}{\dfrac{6.4 }{\sqrt{64} }}[/tex]

[tex]\rm z = \dfrac{2}{\dfrac{6.4 }{8}}[/tex]

Further, simplify the above expression.

z = 2.5

According to the normal distribution table, the probability that their mean blood pressure will be less than 126 is:

P(z < 2.5) = 0.9938

So, the probability is 99.38%.

For more information, refer to the link given below:

https://brainly.com/question/21586810