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Archimedes needs your help determining whether the new crown made for the king by a local jeweler is authentic. What is the buoyant force that he should expect from a 0.50 kg solid gold crown when it is immersed in water? The density of gold is 19,300 kg/m3 and the density of water is 1000 kg/m3.

Respuesta :

Answer:

Buoyant force is equal to 0.253 N    

Explanation:

We have given mass of the gold m = 0.50 kg

Density of gold [tex]d_g=19300kg/m^3[/tex]

Volume displaced [tex]V_{dis}=\frac{mass}{density}=\frac{0.5}{19300}=2.59\times 10^{-5}m^3[/tex]

Density of water [tex]d_w=1000m^3[/tex]

So buoyant force of water is equal to [tex]F_b=d_g\times v_{dis}\times g[/tex]

[tex]F_b=1000\times 2.59\times 10^{-5}\times 9.8=0.253N[/tex]

Buoyant force is equal to 0.253 N

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