Diiodine pentoxide (I2O5) is used in respirators to remove carbon monoxide (CO) from air according to the chemical equation: I2O5 (s) + 5 CO (g) --> I2 (s) + 5 CO2 (g) What mass of carbon monoxide could be removed from air by a respirator that contains 15.9 g of diiodine pentoxide? The molar mass of I2O5 is 333.8 g / mol.

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ruchi86 ruchi86 · Answer 1 · 2020-04-15T15:26:13+02:00

Answer:

mass of that can be removed from air=6.7gram

Explanation:

when you get this type of question first write their balance equation.

First write the balance chemical reaction:

[tex]I_2O_5 (s) + 5 CO (g) \rightarrow I_2 (s) + 5 CO_2 (g)[/tex]

given mass of diiodine pentaoxide=15.9gram

molar mass of diiodine pentaoxide=333.8g/mol

mole of diiodine pentaoxide =15.9/333.8mol

mole of diiodine pentaoxide=0.0476mol

from the above balance equation it is clear that;

1 mole diiodine pentaoxide remove 5 mole of CO from air

0.0476 mole of diiodine pentaoxide will remove [tex]5\times 0.0476[/tex] of CO from air

mole of CO that can be removed=0.238mol

mass of that can be removed from air=6.664gram

mass of that can be removed from air=6.7gram