Answer:
The final speed of the stone as it lift the ground is 23.86 m/s.
Explanation:
Given that,
Force acting on the rock, F = 3 N
Distance, d = 16 m
Initial speed of the stone, u = 22 m/s
We need to find the rock's speed just as it left the ground. It can be calculated using work energy theorem as :
[tex]W=\Delta E\\\\W=\dfrac{1}{2}m(v^2-u^2)\\\\Fd=\dfrac{1}{2}m(v^2-u^2)\\\\v^2=\dfrac{2Fd}{m}+u^2\\\\v^2=\dfrac{2mgd}{m}+u^2\\\\v^2=2\times 9.8\times 16+(16)^2\\\\v=23.86\ m/s[/tex]
So, the final speed of the stone as it lift the ground is 23.86 m/s.
