Answer:
The time measured by the driver of the car measure for his trip between the poles is 2.58 seconds.
Explanation:
Given that,
Let us speed of light in a vacuum has the hypothetical value, c = 18 m/s
A car is moving at a constant speed of 14.0 m/s along a straight road, v = 14 m/s
The observer's time interval is 4.12 s
We need to find the time measured by the driver of the car measure for his trip between the poles. Let it is t. The observer's time interval is given by :
[tex]T=\dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}} }\\\\t=T\times \sqrt{1-\dfrac{v^2}{c^2}} \\\\t=4.12\times \sqrt{1-\dfrac{(14)^2}{(18)^2}} \\\\t=2.58\ s[/tex]
So, the time measured by the driver of the car measure for his trip between the poles is 2.58 seconds.
