Respuesta :
Answer:
4.33 m/s, 5 m/s
Explanation:
mass of car, m = 1000 kg
initial velocity of car, u = 20 m/s along east
mass of truck, M = 2 x mass of car = 2000 kg
initial velocity of truck, U = 0 m/s
After collision, the velocity of car is v and the direction is 30° North of east.
The velocity of truck is V and the direction is 60° South of east.
Use conservation of momentum along X axis.
m x u = m x v x Cos 30 + M x V x Cos 60
1000 x 20 = 1000 x v x 0.866 + 2000 x V x 0.5
20 = 0.866 v + V .... (1)
Use conservation of momentum along y axis
0 = m x v x Sin 30 - M x V x Sin 60
0 = 1000 x v x 0.5 - 2000 x V x 0.866
v = 3.464 V ..... (2)
Substitute the value of v in equation (1)
20 = 0.866 x 3.464 V + V
V = 5 m/s
v = 0.866 x 5 = 4.33 m/s
Thus, the final speed of car is 4.33 m/s and the final speed of truck is 5 m/s after the collision.
