Consider a step-down transformer with 15 turns in the primary and 6 turns in the secondary windings. Calculate the input impedance of this transformer loaded to an 8 Ω resistor, assuming that series resistances of the windings are negligible.

Respuesta :

Answer:

Input impedance of this transformer is 50 ohms.  

Explanation:

Given that,

Number of turns in the primary coil, [tex]N_p=15[/tex]

Number of turns in the secondary coil, [tex]N_s=6[/tex]

Output impedance of the transformer, [tex]V_o=8\ \Omega[/tex]

The number of turns and the impedance ratio in the step down transformer is given by :

[tex]\dfrac{15}{6}=\sqrt{\dfrac{Z_p}{Z_s}}\\\\\dfrac{15}{6}=\sqrt{\dfrac{Z_p}{8}}\\\\Z_p=50\ \Omega[/tex]

So, the input impedance of this transformer is 50 ohms. Hence, this is the required solution.