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Rh-positive individuals have the Rh antigen on their red blood cells, while Rh-negative individuals do not. If the Rh-positive phenotype is produced by a dominant gene (A), and the Rh-negative phenotype is due to its recessive allele

(a). what is the frequency of the Rh-positive allele if 84% of a population is Rh-positive?

Respuesta :

Answer:

Frequency of the Rh-positive allele [tex]= 0.6[/tex]

Explanation:

Given-

A represents the dominant gene i.e Rh-positive

a represents the recessive gene i.e Rh-negative

It is given that 84% of a population is Rh-positive. This means that 84% of a population will have genotype either Aa or AA

Now as per Hardy Weinberg's equation -

[tex]p^2[/tex]  is the frequency of Aa or AA genotype

[tex]q^2[/tex] is the frequency of aa genotype

Frequency of recessive allele

[tex]\sqrt{q} \\= \sqrt{(1-0.84} \\= \sqrt{0.16} \\= 0.4[/tex]

As per first equation of HW equilibrium -

[tex]p + q = 1[/tex]

Substituting the value of q in above equation , we get

[tex]p + 0.4 = 1\\p = 1-0.4\\p =0.6[/tex]

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