Answer:
3.8 secs
Explanation:
Parameters given:
Acceleration due to gravity, g = 9.8 [tex]m/s^2[/tex]
Initial velocity, u = 11.76 m/s
Final velocity, v = 49 m/s
Using one of Newton's equations of linear motion, we have that:
[tex]v = u + gt[/tex]
where t = time of flight of arrow
The sign is positive because the arrow is moving downward, in the same direction as gravitational force.
Therefore:
[tex]49 = 11.76 + 9.8*t\\\\\\\49 - 11.76 = 9.8t\\\\=> 9.8t = 37.24\\\\\\t = \frac{37.24}{9.8} \\\\\\t = 3.8 secs[/tex]
The arrow was in flight for 3.8 secs
