5.85 The gas from a certain volcano had the following composition in mole percent (that is, mole fraction x 100); 65.0% CO2, 25.0% H2, 5.4% HCl, 2.8% HF, 1.7% SO2 and 0.1% H2S. What would be the partial pressure of each of these gases if the total pressure of volcanic gas were 760 mmHg

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thomasdecabooter thomasdecabooter · Answer 1 · 2020-04-16T05:42:29+02:00

Answer:

Partial pressure CO2 = 494 mmHg

Partial pressure H2 = 190 mmHg

Partial pressure HCl = 41.04 mmHg

Partial pressure HF = 21.28 mmHg

Partial pressure SO2 = 12.92 mmHg

Partial pressure H2S = 0.76

Explanation:

Step 1: Data given

Composition

CO2 = 65.0 %

H2 = 25.0 %

HCl = 5.4 %

HF = 2.8 %

SO2 = 1.7 %

H2S = 0.1 %

total pressure of volcanic gas were 760 mmHg

Step 2= Calculate partial pressure

Partial pressure = total pressure * mol fraction

Partial pressure CO2 = 760mm Hg* 0.65

Partial pressure CO2 = 494 mmHg

Partial pressure H2 = 760 mmHg * 0.25

Partial pressure H2 = 190 mmHg

Partial pressure HCl = 760 mmHg * 0.054

Partial pressure HCl = 41.04 mmHg

Partial pressure HF = 760 mmHg * 0.028

Partial pressure HF = 21.28 mmHg

Partial pressure SO2 = 760 mmHg * 0.017

Partial pressure SO2 = 12.92 mmHg

Partial pressure H2S = 760 mmHg * 0.001

Partial pressure H2S = 0.76 mmHg