Answer:
Intensity S = 4.446 W/m²
Amount of Energy U = 1.834 J
Explanation:
Given that:
[tex]E_{max[/tex] = 57.9 V/m
Area A = 0.0223 m²
Time t = 18.5 s
Then; Intensity (S) = [tex]\frac{(E_{max})^2}{2 \ \mu_o \ C}[/tex]
where;
[tex]\mu_o = 4 \pi *10 ^{-7}[/tex]
[tex]C = 3*10^8[/tex]
∴ S = [tex]\frac{(57.9)^2}{2*(4 \pi *10^{-7})*(3*10^8 )}[/tex]
S = 4.446 W/m²
Energy flow U = S*A*t
U = 4.446×0.0223×18.5
U = 1.834 J
