Respuesta :
Answer:
100% Wavy hair
Explanation:
The gene involved here codes for hair texture in humans. The alleles of the gene (straight, S and curly, s) exhibits incomplete dominance. Incomplete dominance is a genetic scenario whereby one allele does not completely mask the expression of the other allele, instead an intermediate phenotype that is heterozygous is formed.
In this case, a man with curly hair (ss) marries a woman with straight hair (SS). The children from this cross will all possess a heterozygous genotype (Ss) and be phenotypically wavy-haired, since Incomplete dominance is exhibited by the gene. Therefore, 100% of the offsprings/children will have wavy hair phenotype.
Answer:
100% wavy haired
Explanation:
Let the allele for curly hair texture be represented by C and the allele for for straight hair texture be c.
A man with curly hair will have the genotype CC.
A woman with straight hair will have the genotype cc.
Crossing the two in marriage:
CC x cc
Progeny: Cc, Cc, Cc and Cc.
Recall that the hair texture gene exhibit incomplete dominance, meaning that heterozygous individuals have intermediate attribute - wavy hair.
Hence, all the children will have wavy hair.