Answer:
[tex]P_{2} = 527.803\,kPa[/tex]
Explanation:
The politropic relationship for a isentropic process is:
[tex]\frac{P_{2}}{P_{1}} = \left(\frac{V_{1}}{V_{2}} \right)^{\gamma}[/tex]
Where [tex]\gamma[/tex] is the ratio of specific heats
The final pressure is:
[tex]P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}}\right)^{\gamma}[/tex]
[tex]P_{2} = (200\,kPa)\cdot (2)^{1.4}[/tex]
[tex]P_{2} = 527.803\,kPa[/tex]
