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wo bars are conducting heat from a region of higher temperature to a region of lower temperature. The bars have identical lengths and cross-sectional areas, but are made from different materials. In the drawing they are placed "in parallel" between the two temperature regions in arrangement A, whereas they are placed end to end in arrangement B. In which arrangement is the heat that is conducted the greatest?

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Answer:

Explanation:

Use radiant energy formula according for Stefan-Boltzmann law,

Qnet/t = AeσT4

Qnet is radiant energy, t is time, σ is Stefan constant, e is emissivity , A is cross sectional area and T is temperature.

Qnet(A)/t = (L0)2eσ(4T0)4 = 256L02eσT04

Qnet(B)/t = (2L0)2eσ(3T0)4 = 85L02eσT04

Qnet(C)/t = (3L0)2eσ(2T0)4 = 25L02eσT04

Thus, Qnet(A)/t > Qnet(B)/t > Qnet(C)/

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