Give the coordination number, the charge of the central metal ion, and select the correct name in each coordination compound: A. Na3[CoCl6] coordination number charge of the central metal ion name B. [Ni(CO)4] coordination number charge of the central metal ion name C. [Ni(NH3)3(H2O)3] (NO3)2 coordination number charge of the central metal ion name

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The correct question is

Give the coordination number, the charge of the central metal ion, and select the correct name in each coordination compound:

Na3[CoCl6]

[Ni(CO)4]

[Ni(NH3)3(H2O)2] (NO3)2

Answer:

See explanation for details

Explanation:

Na3[CoCl6]

Name: Sodium hexacholorocobalt III

Charge on the complex: -3

Central metal ion name : cobalt III

coordination number: 6

[Ni(CO)4]

Name: tetracarbonyl nickel (0)

Charge on the complex: 0

Central metal ion name : nickel (0)

coordination number: 4

[Ni(NH3)3(H2O)2] (NO3)2

Name: Diaquatriaminenickel II nitrate

Charge on the complex: +2

Central metal ion name : nickel (+2)

coordination number: 5

Answer:

  • A) [tex]Na_3 [CoCl_6][/tex] :

Cordination number = [tex]6[/tex]

Charge = [tex]+3[/tex]

Name = [tex]Sodium hexachlorocobaltate III[/tex]

  • B) [tex][Ni(CO)_4][/tex] :

Cordination number = [tex]4[/tex]

Charge = [tex]0[/tex]

Name = [tex]Tetracarbonyl Nickel 0[/tex]

  • C)[tex][Ni(NH_3)_3(H_2O)_3] (NO_3)_2[/tex]

Cordination number = [tex]5[/tex]

Charge = [tex]+2[/tex]

Name = [tex]DiaquatriamineNickel II Nitrate[/tex]

Explanation:

A. [tex]Na_3[CoCl_6][/tex]

Central metal atom is Cobalt

There are three Sodium cations

There are six chloride ligands

The oxidation number,

[tex]= x - (6*1) + 3 =0\\\\x = +3[/tex]

B. [tex][Ni(CO)_4][/tex]

Central metal atom is Nickel

There are four Carbon Monoxide (0) ligands

The oxidation number,

[tex]= x + (4*0) = 0\\\\x = 0[/tex]

C. [tex][Ni(NH_3)_3(H_2O)_3] (NO_3)_2[/tex]

Central metal atom is Nickel

There are two Nitrate (-1) anions

There are threee ammonia (0) ligands

There are two water (0) ligand also

oxidation number,

[tex]x - (2*1) + (3*0) + (2*0) = 0\\\\x = +2[/tex]

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