Answer:
Solution of each part is given below .
Explanation:
Given :
Wavelength of laser in air is , [tex]\lambda=632.8\ nm[/tex] .
We know its velocity in air is , [tex]c=3\times 10^8\ m/s[/tex] .
So , its frequency is ,
[tex]f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{632.8\times 10^{-9}}\\\\f=4.74\times 10^{14}\ s^{-1}[/tex]
We know , frequency is source dependent only and since the source is same so frequency will be same and equal to [tex]f=4.74\times 10^{14}\ s^{-1}[/tex] .
Therefore , its velocity in Lucite is :
[tex]v=\dfrac{c}{\mu}\\\\v=\dfrac{3\times 10^8}{1.5}\\\\v=2\times 10^8\ m/s[/tex]
New wavelength is :
[tex]\lambda'=\dfrac{v}{f}\\\\\lambda'=\dfrac{2\times 10^8}{4.74\times 10^{14}}\\\\\lambda'=4.219\times 10^{-7}\ m\\\\\lambda'=421.9\ nm[/tex]
Hence , this is the required solution .
