contestada

If triangle abc is similar to triangle def with ab=9, bc=11, and ac=16, then which of the following is closest to the ratio of de to df?

Respuesta :

calculista

Answer:

[tex]\frac{de}{df}=\frac{9}{16}[/tex]  or [tex]\frac{de}{df}=0.5625[/tex]

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional

so

In this problem

Triangle abc is similar to Triangle def

therefore

[tex]\frac{de}{df}=\frac{ab}{ac}[/tex]

substitute the given values

[tex]\frac{de}{df}=\frac{9}{16}[/tex]

abidemiokin

The ratio of the side DE to DF is 9:16

Similar triangles

From the given question, we are told that triangle ABC is similar to DEF, this shows that:

AB = DE

AC = DF and;

BC = EF

GIven the following parametrs

ab=9, bc=11, and ac=16, then the similar sides in DEF will be:

DE = 9 and DF = 16

Take the ratio of DE to DF;

Ratio = DE/DF = 9/16

Hence the ratio of the side DE to DF is 9:16

Learn more on similar triangle here: https://brainly.com/question/2644832

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