Answer:
The minimum required thickness for a steel pressure vessel (t) is 2.275 mm
Explanation:
Minimum required thickness is the thickness of a material without corrosion allowance for each component based on the appropriate design that consider pressure, mechanical and structural loading.
Given that:
radius (r) = 65 mm = 65 × 10⁻³ m
Factor of safety (N) = 3.5
Inside presssure ([tex]P_{in}[/tex]) = 11 MPa
Outside pressure ([tex]P_{out}[/tex]) = 1 MPa
Yield strength ([tex]\sigma_y[/tex]) = 1000 MPa
Therefore:
[tex]\sigma_y =\frac{\sigma_y}{N}[/tex], Substituting values,
[tex]\sigma_y =\frac{\sigma_y}{N}=\frac{1000}{3.5}=285.714 MPa[/tex]
The minimum required thickness for a steel pressure vessel (t) is given by the equation:
[tex]t=\frac{r.(P_{in}-P_{out})}{\sigma_y}[/tex]. Substituting values
[tex]t=\frac{r.(P_{in}-P_{out})}{\sigma_y}=\frac{65*10^{-3} *(11-1)10^{6} }{285.714*10^{6} } =2.275*10^{-3} =2.275 mm[/tex]
The minimum required thickness for a steel pressure vessel (t) is 2.275 mm
