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In a hydraulic press, the large piston of cross-sectional area A1 = 200 cm2 and the small piston has the cross-sectional area A2 = 5 cm2. If a force of 250 N is applied to the small piston, what is the magnitude of force F on the large piston?
a. 10 N
b. 1000 dyn
c. 1000 N
d. 10 kN

Respuesta :

Kazeemsodikisola

Answer:

Explanation:

Given that,

Cross sectional area A1 = 200cm²

Cross-sectional area A2 = 5cm²

F2 = 250N is force is applied at the smaller area

F1=?

Using Pascal principle

Pressure at the small area = Pressure at the larger area

Pressure is given as P= F/A

F1/A1 = F2/A2

F1/200 = 250/5

F1/200 = 50

F1 = 50×200

F1 = 10,000N

1kN = 1000N

F1 = 10KN

The correct answer is D

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