Answer:
The line-of-sight distance from the television camera to the case of the stadium is x = 3282.20 m
Step-by-step explanation:
Given data
From Δ ABC
AB = The altitude of the blimp is = 400 m
AC = The line-of-sight distance from the television camera to the case of the stadium = x
Now
[tex]\sin7 = \frac{AB}{AC}[/tex]
[tex]x = \frac{AB}{\sin7}[/tex]
[tex]x = \frac{400}{\sin7}[/tex]
x = 3282.20 m
Therefore the line-of-sight distance from the television camera to the case of the stadium.
