The presence of freckles is due to a dominant allele. Four percent of the individuals in a particular population lack freckles. Use the Hardy-Weinberg formula to calculate the percentage of individuals in this population who are homozygous dominant for freckles.
a) 32%
b) 80%
c) 64%
d) 20%
e) 4%

Respuesta :

Answer:

Option C

Explanation:

Allele for dominant freckle trait is "F"

Allele for recessive no freckle trait is "f"

Given -

Population lacking freckles  [tex]= 4[/tex]%

As per Hardy Weinberg's equilibrium equation

p represents the frequency of dominant allele in a given population and [tex]p^2[/tex] represents the frequency of dominant individuals in a given population

Like wise

q  represents the frequency of recessive allele in a given population and [tex]q^2[/tex] represents the frequency of recessive individuals in a given population

[tex]q^2 = 0.04\\q = 0.2[/tex]

Frequency of dominant allele [tex]= 1- 0.2\\= 0.8[/tex]

Frequency of homozygous recessive individual

[tex]q^2 = 0.4[/tex]

Frequency of homozygous dominant individual

[tex]q^2 = 0.4[/tex][tex]0.8^2\\= 0.64[/tex]

Option C is correct