Two carts with masses of 12.5 kg and 3.5 kg, respectively, move in opposite directions on a frictionless horizontal track with speeds of 6.0 m/s and 1.0 m/s, respectively. The carts stick together after colliding head-on. Find the final speed of the two carts. m/s

Respuesta :

Answer:

Explanation:

Parameters given:

Mass of first cart, m = 12.5 kg

Mass of second cart, M = 3.5 kg

Initial velocity of first cart, u = 6.0 m/s

Initial velocity of second cart, v = 1.0 m/s

NOTE: Both carts stick together after collision, hence, they have the same final velocity, v

Using the principle of conservation of momentum, we have that the total initial momentum of the system is equal to the final momentum of the system:

Total Initial Momentum = Total Final Momentum

mu + MU = (m + M)v

Making v subject of formula:

[tex]v = \frac{mu+MU}{m + M}[/tex]

[tex]v = \frac{(12.5 * 6) + (3.5 * 1)}{12.5 + 3.5 } \\\\\\v = \frac{75 + 3.5}{16} \\\\\\v = \frac{78.5}{16}\\ \\\\v = 4.91 m/s[/tex]

The final speed of the two carts is 4.91 m/s.