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A commercial enclosed gear drive consists of a 20° spur pinion having 16 teeth driving a 48-tooth gear. The pinion speed is 300 rev/min, the face width 2.25 in, and the diametral pitch 6 teeth/in. The gears are grade 1 steel, through-hardened at 200 Brinell, made to No. 6 quality standards, uncrowned, and are to be accurately and rigidly mounted. Assume a pinion life of 10^8 cycles and a reliability of 0.90. Determine the AGMA bending stresses of the gear and the corresponding factors of safety if 5 hp is to be transmitted. Assume Ko = KB = KT = Cf = 1

Respuesta :

Hashirriaz830

Answer:

S_h(new) = 1.29

yes new design S_h>S_h(old)

Explanation:

solution:

Change Np into change Dp, V, [tex]W^{t}[/tex], Y,[tex]K_{v}[/tex], [tex]K_{s}[/tex], I

Dp = Dp(old) = 2.667 ==> Dp(new) = 3.667

V = V(old) = 209.4 ==> V(new) = 288

[tex]W^{t}[/tex] = [tex]W^{t}[/tex](old) = 787.8 ==> [tex]W^{t}[/tex](new) = 573

Y = Y(old) = 0.296 ==> Y(new) = 0.331

[tex]K_{v}[/tex] = [tex]K_{v}[/tex](old) = 1.20 ==>[tex]K_{v}[/tex](new) = 1.23

[tex]K_{s}[/tex] = [tex]K_{s}[/tex](old) = 1.088 ==> [tex]K_{s}[/tex](new) = 1.091

I = I(old) = 0.121 ==> I(new) = 0.110

S_h(new) = S_h(old)*([tex]K_{v}[/tex](old)/[tex]K_{v}[/tex](new))*([tex]W^{t}[/tex](old)/[tex]W^{t}[/tex](new))*([tex]K_{s}[/tex](old)/[tex]K_{s}[/tex](new))*(I(new)/I(old))

S_h(new) = 1.29

yes new design S_h>S_h(old)

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