Answer: a) 2.64 min b) 2.688 min.
Step-by-step explanation:
Since we have given that
Average time in a direct time study = 2.40 min
Worker's performance on all cycles = 110%
Delay allowance for this work = 12%
So, the normal time would be
[tex]2.40(1.10)=2.64\ min[/tex]
and the standard time would be
[tex]2.40(1+0.12)\\\\=2.40\times 1.12\\\\=2.688\ min[/tex]
Hence, a) 2.64 min b) 2.688 min.