A bomb calorimeter has a heat capacity of 783 J/oC and contains 254 g of water whose specific heat capacity is 4.184 J/goC. How much heat, in kilojoules, is evolved or absorbed by a reaction when the temperature goes from 23.73 oC to 26.01 oC? cH2O = 4.184 J/g.K

Respuesta :

Answer : The amount of heat evolved by a reaction is, 4.81 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

[tex]q=[q_1+q_2][/tex]

[tex]q=[c_1\times \Delta T+m_2\times c_2\times \Delta T][/tex]

where,

q = heat released by the reaction

[tex]q_1[/tex] = heat absorbed by the calorimeter

[tex]q_2[/tex] = heat absorbed by the water

[tex]c_1[/tex] = specific heat of calorimeter = [tex]783J/^oC[/tex]

[tex]c_2[/tex] = specific heat of water = [tex]4.184J/g^oC[/tex]

[tex]m_2[/tex] = mass of water = 254 g

[tex]\Delta T[/tex] = change in temperature = [tex]T_2-T_1=(23.73-26.01)=-2.28^oC[/tex]

Now put all the given values in the above formula, we get:

[tex]q=[(783J/^oC\times -2.28^oC)+(254g\times 4.184J/g^oC\times -2.28^oC)][/tex]

[tex]q=-4208.28J=-4.81kJ[/tex]

Therefore, the amount of heat evolved by a reaction is, 4.81 kJ