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The average intensity of light emerging from a polarizing sheet is 0.764 W/m^2, and the average intensity of the horizontally polarized light incident on the sheet is 0.883 W/m^2. Determine the angle that the transmission axis of the polarizing sheet makes with the horizontal.

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Answer:

The angle that the transmission axis of the polarizing sheet makes with the horizontal is 21.55⁰

Explanation:

Given;

average intensity of incident light, I = 0.764 W/m²

average intensity of transmitted light, I₀ = 0.883 W/m²

I = I₀Cos²θ

where;

θ is the angle that the transmission axis of the polarizing sheet makes with the horizontal.

Cos²θ = I / I₀

Cos²θ = 0.764/0.883

Cos²θ = 0.8652

Cosθ = √0.8652

Cosθ = 0.9301

θ = Cos⁻¹ 0.9301

θ = 21.55⁰

Therefore, the angle that the transmission axis of the polarizing sheet makes with the horizontal is 21.55⁰

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