Answer:
Final speed of striped ball is 3 m/s in left direction .
Explanation:
Given :
Two billiard ball with the same mass moves toward the left at the same speed 3 m/s .
Let , us assume right hand side direction to be positive and left hand side direction to be negative .
Also , let speed of ball after collision is (striped ball ) u and (solid ball) v .
It is also given that the collision is elastic .
Therefore , kinetic energy is conserved .
[tex]\dfrac{m(3)^2}{2}+\dfrac{m(3)^2}{2}=\dfrac{mu^2}{2}+\dfrac{mv^2}{2}\\\\u^2+v^2=18[/tex] ...... ( 1 )
Also , by conserving linear momentum .
We get :
[tex]3m-3m=mu+mv\\u=-v[/tex] ...... ( 2 )
Putting value of u from equation 2 to equation 1 .
We get :
[tex]2v^2=18\\v=3\ m/s[/tex]
And , u = -3 m/s .
Therefore , final speed of striped ball is 3 m/s in left direction .
Hence , this is the required solution .
