Respuesta :
Answer:
The rate of rowing team in still water is = 6 [tex]\frac{mi}{hr}[/tex]
Explanation:
Let speed of the team in still water = u [tex]\frac{mi}{hr}[/tex]
speed of the current = v [tex]\frac{mi}{hr}[/tex]
Upstream velocity = u - v
Downstream velocity = u + v
Given that
Distance covered in downstream is twice the Distance covered in upstream.
[tex]\frac{50}{u + v} = \frac{25}{u - v}[/tex]
[tex]\frac{2}{u + v} = \frac{1}{u - v}[/tex]
[tex]2 u - 2 v = u + v\\[/tex]
u = 3 v
Rate of current (v) = 2 [tex]\frac{mi}{hr}[/tex]
u = 3 × v = 3 × 2
u = 6 [tex]\frac{mi}{hr}[/tex]
Therefore the rate of rowing team in still water is = 6 [tex]\frac{mi}{hr}[/tex]
