Answer:
The velocity and height is 31 m/s and 44.4 m respectively .
Explanation:
Given :
Initial speed of rock , u = 8.5 m/s .
Time taken to reach ground , t = 2.25 s .
Also , acceleration due to gravity is , [tex]g=10\ m/s^2[/tex] .
Now , to find the velocity when it hit ground .
Applying equation of motion :
[tex]v=u+at\\v=8.5+10\times 2.25\\v=31\ m/s[/tex]
Also , height from which rock is thrown is given by :
[tex]h=ut+\dfrac{at^2}{2}\\\\h=8.5\times 2.25+\dfrac{10\times 2.25^2}{2}\\\\h=44.4\ m[/tex]
Hence , this is the required solution .
