Answer:
33.0 m
Explanation:
We are given that
Wavelength,[tex]\lambda=550nm=550\times 10^{-9} m[/tex]
[tex]1nm=10^{-9} m[/tex]
Diameter of pupil=d=5.1 mm=[tex]5.1\times 10^{-3} m[/tex]
[tex]1mm=10^{-3} m[/tex]
[tex]y=4.35 mm=4.35\times 10^{-3}m[/tex]
By Rayleigh criteria
[tex]sin\theta=1.22\frac{\lambda}{d}[/tex]
[tex]\frac{y}{L}=1.22\frac{\lambda}{d}[/tex]
[tex]L=\frac{yd}{1.22\lambda}[/tex]
Substitute the values
[tex]L=\frac{4.35\times 10^{-3}\times 5.1\times 10^{-3}}{1.22\times 550\times 10^{-9}}[/tex]
[tex]L=33.0 m[/tex]
