Answer: a) 1.729, b) 2.712, c) 3.169, d) 2.602.
Step-by-step explanation:
Since we have given that
a) one-tail test, alpha = 0.05, and n = 20
So, the degree of freedom = [tex]n-1=20-1=19[/tex]
So, [tex]t_{19}=1.729[/tex]
b) one-tail test, alpha = 0.005, and n = 39
So, the degree of freedom = [tex]n-1=39-1=38[/tex]
So, [tex]t_{38}=2.712[/tex]
c) two-tail test, alpha = 0.10, and n = 11
So, the degree of freedom = [tex]n-1=11-1=10[/tex]
So, [tex]t_{10}=3.169[/tex]
d) two-tail test, alpha = 0.02, and n = 16
So, the degree of freedom = [tex]n-1=16-1=15[/tex]
So, [tex]t_{15}=2.602[/tex]
Hence, a) 1.729, b) 2.712, c) 3.169, d) 2.602.