A) Two wavy haired people (one male and one female) have eight children. Of these eight, how many would you expect to be curly haired, how many wavy haired, and how many straight haired, assuming that the family follows the expected statistically predicted pattern?
B) Suppose you examine the actual children and discover that three of the eight have curly hair. What do you suppose when wrong?

Respuesta :

Answer: Following the statistically predicted pattern all children are expected to have wavy hair since there was no indication that either parent possessed an allele for curly hair.

If discovered that 3 out of the right children had curly hair,then one of the parent had an allele for curly hair but the allele is recessive

Explanation:

The rules of probability can be applied to Mendelian crosses or normal crosses to determine the predicted or expected genotype and phenotypes of the offspring.

The answers can be explained as:

(A) The statistical prediction of children having wavy hair will be zero. The allele for the wavy hairs and curly hairs are not mentioned, and therefore, it will not be possible to statistically predict the phenotype of the offspring.

(B) It is given that, 3 out of eight children have curly hair. The phenotype of the offspring will suggest that one of the parents will have the allele for curly hair, which is recessive.

To know more about the inheritance, refer to the following link:

https://brainly.com/question/25632001