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URGENT PLEASE HELP!!!!
(04.03 HC) Given the function g(x) = 4(3)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4. Part A: Find the average rate of change of each section. (4 points) Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points) (10 points)

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asialeigh2007

Answer:

Part A: 24

Part B: 216

Step-by-step explanation:

Part A:

[tex]\frac{g(2)-g(1)}{2-1}[/tex] ----->>> [tex]\frac{4(3)^{2} -4(3)^{1} }{1}[/tex]

[tex]\frac{36-12}{1}[/tex] = 24

Part B:

[tex]\frac{g(4)-g(3)}{4-3}[/tex] ------>>> [tex]\frac{4(3)^{4} 4(3)^{3} }{1}[/tex]

[tex]\frac{324-108}{1}[/tex]= 216

hope this helps you a bit!! :)

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