Answer:
[tex]\lambda = 2.22\times 10^{-3}\ m[/tex]
Explanation:
Given,
mass of the bar = 1.1 Kg
length of rod, l = 0.40 m
diameter of the rod, d = 2 cm
frequency, f = 1.5 MHz
time, t = 0.12 ms
wavelength of the shock wave = ?
Speed of the wave =[tex]\dfrac{L}{t}=\dfrac{0.40}{0.12\times 10^{-3}}[/tex]
v = 3333.33 m/s
wavelength of the wave
[tex]\lambda = \dfrac{v}{f}= \dfrac{3333.33}{1.5\times 10^6}[/tex]
[tex]\lambda = 2.22\times 10^{-3}\ m[/tex]
