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Analysis of a bacterial gene indicates that 24% of the nucleotides in the coding strand contain the base A, 18% contain the base T, 26% contain the base G, and 32% contain the base C. What percent of the nucleotides in the mRNA transcribed from this gene will contain the base U

Respuesta :

Answer:

24%

Explanation:

DNA, as given            ATGC  ( A=24%, T= 18%, G= 26% and C= 32%)

 mRNA will be as      UACG   from this DNA

Now as it transcribe into mRNA, in mRNA, as G pairs with C and A pairs with U and T pairs with A.

So, in mRNA A will be 18% equal to T in DNA, G will be 32%, C will be 26% and  U will be 24%.

luisvaschetto

If a gene has 18% Thymine nucleotides in the coding strand, then 18% percent of the nucleotides in the mRNA transcribed from this gene will contain the base U.

  • Deoxyribonucleic acid (DNA) is a double helix molecule composed of two long strands of nucleotides.

  • In DNA, there are four types of nucleotides, each one having a different nitrogenous base (i.e., Adenine, Thymine, Cytosine and Guanine).

  • In RNA, Thymine bases are replaced by Uracil bases, thereby the content of Thymine in DNA is equal to the content of Uracil in RNA.

In conclusion, if a gene has 18% Thymine nucleotides in the coding strand, then 18% percent of the nucleotides in the mRNA transcribed from this gene will contain the base U.

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https://brainly.com/question/18589623

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