Answer:
The longitudinal displacement is 1.373x10⁻⁵m
Explanation:
Given:
f = 384 Hz
λ = 0.55 m
x = 2.4 m
t = 6.7 ms = 6.7x10⁻³s
sm = 14 µm = 14x10⁻⁶m
According the question, the displacement is:
[tex]s=s_{m} cos(kx-wt)[/tex]
But:
[tex]k=\frac{2\pi }{\lambda } =\frac{2\pi }{0.55} =11.42[/tex]
[tex]w=2\pi f=2\pi *384=2412.74[/tex]
Replacing:
[tex]s=14x10^{-6} cos(11.42x-2412.74t)\\s=14x10^{-6} cos((11.42*2.4)-(2412.74*6.7x10^{-3}))\\ s=1.373x10^{-5} m[/tex]
