The maximum force on the supporting cable is 50,762 N.
The minimum force on the supporting cable is 44,298 N.
The given parameters;
- mass of the elevator, m = 4850 kg
- maximum acceleration of the elevator, a = 0.068g
The maximum force on the supporting cable is obtained when the elevator is moving upwards;
T = W + ma
T = mg + ma
T = m(g + a)
T = 4850(g + 0.068g)
T = 4850(1.068g)
T = 4850(1.068 x 9.8)
T = 50,762 N
The minimum force on the supporting cable is obtained when the elevator is moving downwards;
T = W - ma
T = mg - ma
T = m(g - a)
T = m(g - 0.068g)
T = m(0.932g)
T = 4850(0.932 x 9.8)
T = 44,298 N
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