Respuesta :
Answer:
8.3 moles
Explanation:
Step 1:
Data obtained from the question. This includes:
Initial volume (V1) = 8.15 L
Initial mole (n1) = 8.51 mol
Final volume (V2) = 16.1 L
Number of mole added =?
Final mole (n2) =?
Step 2:
Obtaining an equation to solve for the final mole. This is illustrated below:
From ideal gas equation,
PV = nRT
Divide both side by P
V = nRT/P
Divide both side by n
V/n = RT/P
Since pressure (P) and temperature (T) are constant, therefore
V/n = constant
V1/n1 = V2/n2
Step 3:
Determination of the final mole. This is illustrated below:
Initial volume (V1) = 8.15 L
Initial mole (n1) = 8.51 mol
Final volume (V2) = 16.1 L
Final mole (n2) =?
V1/n1 = V2/n2
8.15/8.51 = 16.1/n2
Cross multiply to express in linear form
8.15 x n2 = 8.51 x 16.1
Divide both side by 8.15
n2 = (8.51 x 16.1) / 8.15
n2 = 16.81 moles
Therefore, the final mole is 16.81 moles
Step 4:
Determination of the number of moles added. This can be obtained as illustrated below:
Number of mole added = final mole - initial mole
Number of mole added = n2 - n1
Number of mole added = 16.8 - 8.51
Number of mole added = 8.3 moles
Answer:
When the volume change to 16.1 L; the number of moles increases to 16.8 moles. This means we add 8.29 moles.
Explanation:
Step 1: Data given
The initial volume of the container = 8.15 L
Number of moles of gas= 8.51 moles
The volume increases to 16.1 L
The pressure and temperature of the gas remain constant
Step 2: Calculate the new number of moles
V1/n1 = V2/n2
⇒with V1 = the initial volume in the container = 8.15 L
⇒with n1 = the initial number of gas = 8.51 moles
⇒with V2 = the increased volume = 16.1 L
⇒with n2 = the new number of moles = TO BE DETERMINED
8.15 L / 8.51 moles = 16.1 L / n2
n2 = 16.1 L / (8.15 L / 8.51 moles)
n2 = 16.8 moles
When the volume change to 16.1 L; the number of moles increases to 16.8 moles
The number of moles added = 16.8 - 8.51 = 8.29 moles
