Respuesta :
Answer:
The energy used to reach the surface is 1.53 eV.
Explanation:
Given that, the work function of a certain metal is 6.6 eV.
Frequency of photon, [tex]f=2.8\times 10^{15}\ Hz[/tex]
Kinetic energy of the electron, [tex]E=3.5\ eV[/tex]
The energy of the photon is:
[tex]E=hf\\\\E=6.63\times 10^{-34}\times 2.8\times 10^{15}\\\\E=1.85\times 10^{-18}\ J[/tex]
Energy utilized by the photon is given by :
[tex]hf=W+\dfrac{1}{2}mv^2\\\\hf=6.6+3.5\\\\hf=10.1\ eV\\\\hf=10.1\times 1.6\times 10^{-19}\ J\\\\hf=1.61\times 10^{-18}\ J[/tex]
Used energy is given by the difference of energy given and the energy utilized. So,
[tex]E=(18.55-16.1)\times 10^{-19}\\E=2.45\times 10^{-19}\ J\\\\E=\dfrac{2.45\times 10^{-19}}{1.6\times 10^{-19}}\\\\E=1.53\ eV[/tex]
So, energy used to reach the surface is 1.53 eV.
